作业帮函数f(x)=更号2sin(x+π/4)+2sinxcosx在区间[π/4,π/2]上的最大值是
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![函数f(x)=更号2sin(x+π/4)+2sinxcosx在区间[π/4,π/2]上的最大值是](/uploads/image/z/11616970-58-0.jpg?t=%E5%87%BD%E6%95%B0f%28x%29%3D%E6%9B%B4%E5%8F%B72sin%28x%2B%CF%80%2F4%29%2B2sinxcosx%E5%9C%A8%E5%8C%BA%E9%97%B4%5B%CF%80%2F4%2C%CF%80%2F2%5D%E4%B8%8A%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E6%98%AF)
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函数f(x)=更号2sin(x+π/4)+2sinxcosx在区间[π/4,π/2]上的最大值是
函数f(x)=更号2sin(x+π/4)+2sinxcosx在区间[π/4,π/2]上的最大值是
函数f(x)=更号2sin(x+π/4)+2sinxcosx在区间[π/4,π/2]上的最大值是
f(x)=sinx+cosx+2sinxcosx =sinx+cosx+(sinx+cosx)-1 令t=sinx+cosx=更号2sin(x+π/4) t属于[根号2,2] ∴f(x)=t+t-1 f(x)max=5 t=2时
函数f(x)=更号2sin(x+π/4)+2sinxcosx在区间[π/4,π/2]上的最大值是
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