1.如图1,E是矩形ABCD边AD上一点,且BE=ED,P是对角线BD上任一点,PF垂直BE,PG垂直AD,垂足分别为F、G,则PF+PG=AB成立吗?为什么?
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![1.如图1,E是矩形ABCD边AD上一点,且BE=ED,P是对角线BD上任一点,PF垂直BE,PG垂直AD,垂足分别为F、G,则PF+PG=AB成立吗?为什么?](/uploads/image/z/11722911-15-1.jpg?t=1.%E5%A6%82%E5%9B%BE1%2CE%E6%98%AF%E7%9F%A9%E5%BD%A2ABCD%E8%BE%B9AD%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E4%B8%94BE%3DED%2CP%E6%98%AF%E5%AF%B9%E8%A7%92%E7%BA%BFBD%E4%B8%8A%E4%BB%BB%E4%B8%80%E7%82%B9%2CPF%E5%9E%82%E7%9B%B4BE%2CPG%E5%9E%82%E7%9B%B4AD%2C%E5%9E%82%E8%B6%B3%E5%88%86%E5%88%AB%E4%B8%BAF%E3%80%81G%2C%E5%88%99PF%2BPG%3DAB%E6%88%90%E7%AB%8B%E5%90%97%3F%E4%B8%BA%E4%BB%80%E4%B9%88%3F)
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