关于三角形三线合一.ABC为等腰三角形△ABC中,AB=AC,点D在BC上,∠BAD=∠CAD,所以AD⊥BC,BD=CD.想问一下AB=AC,点D在BC上为什么.能证明BD=BC?
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![关于三角形三线合一.ABC为等腰三角形△ABC中,AB=AC,点D在BC上,∠BAD=∠CAD,所以AD⊥BC,BD=CD.想问一下AB=AC,点D在BC上为什么.能证明BD=BC?](/uploads/image/z/11922121-1-1.jpg?t=%E5%85%B3%E4%BA%8E%E4%B8%89%E8%A7%92%E5%BD%A2%E4%B8%89%E7%BA%BF%E5%90%88%E4%B8%80.ABC%E4%B8%BA%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2%E2%96%B3ABC%E4%B8%AD%EF%BC%8CAB%3DAC%2C%E7%82%B9D%E5%9C%A8BC%E4%B8%8A%EF%BC%8C%E2%88%A0BAD%3D%E2%88%A0CAD%EF%BC%8C%E6%89%80%E4%BB%A5AD%E2%8A%A5BC%EF%BC%8CBD%3DCD.%E6%83%B3%E9%97%AE%E4%B8%80%E4%B8%8BAB%3DAC%2C%E7%82%B9D%E5%9C%A8BC%E4%B8%8A%E4%B8%BA%E4%BB%80%E4%B9%88.%E8%83%BD%E8%AF%81%E6%98%8EBD%3DBC%EF%BC%9F)
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