如果(x+y)+(y-1)i=(2x+3y)+(2y+1)i 求实数xy的值.
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如果(x+y)+(y-1)i=(2x+3y)+(2y+1)i 求实数xy的值.
如果(x+y)+(y-1)i=(2x+3y)+(2y+1)i 求实数xy的值.
如果(x+y)+(y-1)i=(2x+3y)+(2y+1)i 求实数xy的值.
左右两边实部相等,虚部相等,解得y=-2、x=4、xy=-4
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