求y=√(a^2-x^2)的导数,我有一步不懂,y'= (a²-x²)' / [2√(a²-x²)]= -2x / [2√(a²-x²)]我不懂的是“ (a²-x²)' “这个怎么来的啊,根据幂函数的求导公式:y=x^n,y'=nx^(n-1)不是应该
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/16 08:18:05
![求y=√(a^2-x^2)的导数,我有一步不懂,y'= (a²-x²)' / [2√(a²-x²)]= -2x / [2√(a²-x²)]我不懂的是“ (a²-x²)' “这个怎么来的啊,根据幂函数的求导公式:y=x^n,y'=nx^(n-1)不是应该](/uploads/image/z/12077753-41-3.jpg?t=%E6%B1%82y%3D%E2%88%9A%28a%5E2-x%5E2%29%E7%9A%84%E5%AF%BC%E6%95%B0%2C%E6%88%91%E6%9C%89%E4%B8%80%E6%AD%A5%E4%B8%8D%E6%87%82%2Cy%27%3D+%28a%26%23178%3B-x%26%23178%3B%29%27+%2F+%5B2%E2%88%9A%28a%26%23178%3B-x%26%23178%3B%29%5D%3D+-2x+%2F+%5B2%E2%88%9A%28a%26%23178%3B-x%26%23178%3B%29%5D%E6%88%91%E4%B8%8D%E6%87%82%E7%9A%84%E6%98%AF%E2%80%9C+%28a%26%23178%3B-x%26%23178%3B%29%27+%E2%80%9C%E8%BF%99%E4%B8%AA%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84%E5%95%8A%2C%E6%A0%B9%E6%8D%AE%E5%B9%82%E5%87%BD%E6%95%B0%E7%9A%84%E6%B1%82%E5%AF%BC%E5%85%AC%E5%BC%8F%EF%BC%9Ay%3Dx%5En%2Cy%27%3Dnx%5E%28n-1%29%E4%B8%8D%E6%98%AF%E5%BA%94%E8%AF%A5)
xR_KP*acl/A߆$f*MEB!R]dO~ݖ&K/=s߹WI'Pʂ2**z>tyܡUϡV/ 4mwG?ҔHɡ
s(A67!Ʀs1<m
zhk5Ё#,^@8,0UM%n5S[lA8KQn#t]xeicLN>^R0|6]NV ?2,LfH5>2.*$c,
4EgvI9%x`2(