28、如图,等边△ABC中AO是∠BAC的角平分线,D为AO上一点,以CD为一边且在AD下方作等边△CDE,连BE(1)求证:AD=BE(2)延长BE至Q,P为BQ上一点,连结CP,CQ使CP=CQ,若AB=8,PE=3,∠CBP=2∠BCP.求EQ的长
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![28、如图,等边△ABC中AO是∠BAC的角平分线,D为AO上一点,以CD为一边且在AD下方作等边△CDE,连BE(1)求证:AD=BE(2)延长BE至Q,P为BQ上一点,连结CP,CQ使CP=CQ,若AB=8,PE=3,∠CBP=2∠BCP.求EQ的长](/uploads/image/z/12142510-70-0.jpg?t=28%E3%80%81%E5%A6%82%E5%9B%BE%2C%E7%AD%89%E8%BE%B9%E2%96%B3ABC%E4%B8%ADAO%E6%98%AF%E2%88%A0BAC%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%2CD%E4%B8%BAAO%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E4%BB%A5CD%E4%B8%BA%E4%B8%80%E8%BE%B9%E4%B8%94%E5%9C%A8AD%E4%B8%8B%E6%96%B9%E4%BD%9C%E7%AD%89%E8%BE%B9%E2%96%B3CDE%2C%E8%BF%9EBE%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9AAD%3DBE%EF%BC%882%EF%BC%89%E5%BB%B6%E9%95%BFBE%E8%87%B3Q%2CP%E4%B8%BABQ%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E8%BF%9E%E7%BB%93CP%2CCQ%E4%BD%BFCP%3DCQ%2C%E8%8B%A5AB%3D8%2CPE%3D3%2C%E2%88%A0CBP%3D2%E2%88%A0BCP.%E6%B1%82EQ%E7%9A%84%E9%95%BF)
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