lg2^5+2lg2xlg5+2(lg2)^2=
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/26 03:22:34
![lg2^5+2lg2xlg5+2(lg2)^2=](/uploads/image/z/12512676-12-6.jpg?t=lg2%5E5%2B2lg2xlg5%2B2%28lg2%29%5E2%3D)
x)I736R9@gdkT[RΆާ}5aQ k~O'BH!(2Z9 LO9k_\gr" #R
lg2^5+2lg2xlg5+2(lg2)^2=
lg2^5+2lg2xlg5+2(lg2)^2=
lg2^5+2lg2xlg5+2(lg2)^2=
原式=5lg2+2lg2xlg5+2(lg2)^2=lg2(5+2lg5+2lg2)=lg2(5+2(lg5+lg2))=lg2(5+2*lg(5*2))=lg2*(5+2)=7lg2
lg2^5+2lg2xlg5+2(lg2)^2=
高中数学必修1(对数)(lg2)^2+(lg5)^2+2lg2xlg5=__________
lg^2 5+lg2*lg5+lg2=?
lg2×lg2.5+lg0.2×lg40
lg2×lg2.5+lg0.2×lg40
lg^2 5+lg5*lg2+lg2 怎么算lg^2 5+lg5*lg2+lg2 怎么算
lg2+lg2^2+lg2^3+……+lg2^10=
(lg2)^2+lg2×lg50+lg25
3*(lg2)^2+3(1-lg2)*lg2+2(1-lg2)-lg2+9/2
3*(lg2)^2+3(1-lg2)*lg2+2(1-lg2)-lg2+9/2
lg(5)2次方+2lg2-(lg2)2次方计算
(lg2)平方+lg2/5 (2/5为真数)
lg^2(5)+lg2+lg2乘lg5等于多少?
lg2×lg2.5+lg0.2×lg40 怎么算
lg(底数2)5+lg2*(lg2+lg25)的值等于
求值 :lg5²+lg2*lg50+(lg2)²答案写;2lg5+lg2*lg(5*10)+(lg2)²①=2lg5+lg2*lg5+lg2+(lg2)² ②=2lg5+lg2*(lg5+lg2)+lg2③ .第 ②步怎么得到的怎么就变成了lg2*lg5+lg2?
(lg2)²+(lg5)²+lg2xlg5=?(lg2)²+(lg5)²+lg2xlg5=?麻烦您把步骤也写上
(lg50)^2+lg2*lg50^2+(lg2)^2