若y/x,1/y,1/(x+y)都有意义,则下列等式中,不一定成立的是,说明理由xy/(x^2y)=1/x1/(x-y)=(x+y)/(x^2-y^2)y/(x+1)=y^2/xy+yy/(x+y)=(xy-y^2)/(x^2-y^2)第三个是错的
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/11 05:40:45
![若y/x,1/y,1/(x+y)都有意义,则下列等式中,不一定成立的是,说明理由xy/(x^2y)=1/x1/(x-y)=(x+y)/(x^2-y^2)y/(x+1)=y^2/xy+yy/(x+y)=(xy-y^2)/(x^2-y^2)第三个是错的](/uploads/image/z/12563197-61-7.jpg?t=%E8%8B%A5y%2Fx%2C1%2Fy%2C1%2F%28x%2By%29%E9%83%BD%E6%9C%89%E6%84%8F%E4%B9%89%2C%E5%88%99%E4%B8%8B%E5%88%97%E7%AD%89%E5%BC%8F%E4%B8%AD%2C%E4%B8%8D%E4%B8%80%E5%AE%9A%E6%88%90%E7%AB%8B%E7%9A%84%E6%98%AF%2C%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1xy%2F%28x%5E2y%29%3D1%2Fx1%2F%28x-y%29%3D%28x%2By%29%2F%28x%5E2-y%5E2%29y%2F%28x%2B1%29%3Dy%5E2%2Fxy%2Byy%2F%28x%2By%29%3D%28xy-y%5E2%29%2F%28x%5E2-y%5E2%29%E7%AC%AC%E4%B8%89%E4%B8%AA%E6%98%AF%E9%94%99%E7%9A%84)
xQJ@C:ɧ$ܝ`) `qэ.lk%͝/bi.\\ιs3A`9.8VߧzGd2SlRx(oQ^N&fPJoWLFx@J8xڡj[Ӯ8 oelbN~ŀIp++ENTa=x4bq X AAKPDSvǍTjVJF{E?m/ ,Y
若y/x,1/y,1/(x+y)都有意义,则下列等式中,不一定成立的是,说明理由xy/(x^2y)=1/x1/(x-y)=(x+y)/(x^2-y^2)y/(x+1)=y^2/xy+yy/(x+y)=(xy-y^2)/(x^2-y^2)第三个是错的
若y/x,1/y,1/(x+y)都有意义,则下列等式中,不一定成立的是,说明理由
xy/(x^2y)=1/x
1/(x-y)=(x+y)/(x^2-y^2)
y/(x+1)=y^2/xy+y
y/(x+y)=(xy-y^2)/(x^2-y^2)
第三个是错的
若y/x,1/y,1/(x+y)都有意义,则下列等式中,不一定成立的是,说明理由xy/(x^2y)=1/x1/(x-y)=(x+y)/(x^2-y^2)y/(x+1)=y^2/xy+yy/(x+y)=(xy-y^2)/(x^2-y^2)第三个是错的
第四个不一定成立.因为当x=y且不等于零时,右端分母为零无意义,左端不是零.
若y/x,1/y,1/(x+y)都有意义,则下列等式中,不一定成立的是,说明理由xy/(x^2y)=1/x1/(x-y)=(x+y)/(x^2-y^2)y/(x+1)=y^2/(xy+y)y/(x+y)=(xy-y^2)/(x^2-y^2)
若y/x,1/y,1/(x+y)都有意义,则下列等式中,不一定成立的是,说明理由xy/(x^2y)=1/x1/(x-y)=(x+y)/(x^2-y^2)y/(x+1)=y^2/xy+yy/(x+y)=(xy-y^2)/(x^2-y^2)第三个是错的
若x,y都为正实数,且x+y>2.求证(1+x) /y
x,y都大于零,若x+y=5,求(x+1/x)(y+1/y)的最小值?
证明:无论x,y是为何值分式1/x²+y²+4x+6y+14总有意义
若y-x/√8-x有意义,则x=
(x+y)(x-y)+4(y-1)
已知(x-1)^0,(y-2)^-2在实数范围内均有意义,化简(x^2+y^2)/(x^2-y^2)-(x-y)/(x+y)/2xy/(x+y)^2*(x-y)
若函数y=x-1分之1有意义,自变量x取值范围为?
若函数y=1/x-2有意义,则自变量x的取值范围是?
已知x,y均为有理数,且下列分式都有意义,其中P=x/x-1-y/y-1,Q=1/x-1-1/y-1,比较P,Q的大小、在线等
1/(x+y)(x-y)+1/(x-y)若x+y=0 x-y≠0则一个分式有意义,一个分式无意义.那这个算式有无意义?求秒.
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
已知y=x方-2x+1/x方-1÷x方-x/x+1-1/x+1是说明右边的式子在有意义的的条件下,不论x为何值y的值都不变
若x-y=1,求代数式x(x-y)+y(y-x)+2013的值
若x*x+y*y=x+y-1/2,求x,y的值如题
已知Y=X平方-2X+1/X平方-1除以X平方-X/X+1乘以5x试说明在代数式有意义的情况下,不论x取何值y的值都不变