高一抽象函数题f(xy)=f(x)+f(y)①f(x),x≠0,f(xy)=f(x)+f(y)且f(x)在(0,∞ )上是增函数.求f(1),f(-1)求证f(x)=f(-x),解不等式f(2)+f(x-1/2)≤0②f(x)定义域为R,任意a,b
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![高一抽象函数题f(xy)=f(x)+f(y)①f(x),x≠0,f(xy)=f(x)+f(y)且f(x)在(0,∞ )上是增函数.求f(1),f(-1)求证f(x)=f(-x),解不等式f(2)+f(x-1/2)≤0②f(x)定义域为R,任意a,b](/uploads/image/z/12670907-59-7.jpg?t=%E9%AB%98%E4%B8%80%E6%8A%BD%E8%B1%A1%E5%87%BD%E6%95%B0%E9%A2%98f%EF%BC%88xy%EF%BC%89%3Df%EF%BC%88x%EF%BC%89%2Bf%EF%BC%88y%EF%BC%89%E2%91%A0f%EF%BC%88x%EF%BC%89%2Cx%E2%89%A00%2Cf%EF%BC%88xy%EF%BC%89%3Df%EF%BC%88x%EF%BC%89%2Bf%EF%BC%88y%EF%BC%89%E4%B8%94f%EF%BC%88x%EF%BC%89%E5%9C%A8%EF%BC%880%2C%E2%88%9E+%EF%BC%89%E4%B8%8A%E6%98%AF%E5%A2%9E%E5%87%BD%E6%95%B0.%E6%B1%82f%EF%BC%881%EF%BC%89%2Cf%EF%BC%88-1%EF%BC%89%E6%B1%82%E8%AF%81f%EF%BC%88x%EF%BC%89%3Df%EF%BC%88-x%EF%BC%89%2C%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8Ff%EF%BC%882%EF%BC%89%2Bf%EF%BC%88x-1%2F2%EF%BC%89%E2%89%A40%E2%91%A1f%EF%BC%88x%29%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BAR%2C%E4%BB%BB%E6%84%8Fa%2Cb)
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