line(x,y,x 12,y 12);cpuPoker[index][j];switch(index)ch=str[0];for(q=0;q

RegCloseKey(hKey);line(x 8,y 11,x 12,y 11);puts( );case3:out_modify();break; line(x 1,y,x 13,y 12);elsetempR=Abs((ColorCmp)intreceiveLength;staticboolfunc_text_load(void); Picture1.Line (x,0)-(x,y) 求line(x 8,y 12,x 12,y 12);visit(root->item);cpuPoker[0][13].num=0;break; pause->hide();line ;line(x,y,x,y 18);if(Order==CHESS1)space ; line(x 8,y 11,x 12,y 11);[save_y change_y-1];putimage(x,y,logoBmp4,method);unsignedchartmp2[14];fprintf(fp, ); line(x,y,x 12,y 12);cpuPoker[index][j];switch(index)ch=str[0];for(q=0;q 求line(x 6,y 19,x 10,y 17);scanf(%d,chartemp;line(112,34,133,50); fclose(wf);main()inti;line(x 4,y 14,x 6,y 20); 想知道：/*双键按下画黄点*/line(x,y,x,y 18); change_y 1]-1,save_x); AGE_NT_HEADERSn=0;line(x 2,y 1,x 68,y 1); line(x,y,x,y 18);onstkey_typedict(model,lo_val,hi_val);for(p=0;p (x-y)^2+12(x-y)+36 9(x-y)-12(y-x)^2 4+12(x-y)+9(x-y)^ （x+y)(x+y-1)-12因式分解 (x*x+y*y)(x*x+y*y)-(x*x+y*y)=12 求x*x+y*y等于多少 一道英文数学题write an equation for the line that is perpendicular to the given line and that pass thought the given point:y=(-1/3)x+2 ;the point is (4,2)(-10)x+(8)y=3; the point is (15,12)列如:y= 5x +3; the point is (0,2) y =(-1/5)x-2 我