设A={yl y=y²-1x∈R}.B={yl y=-2y²+2 ,x∈R},求A∩B设A={yl y=x²-1x∈R}.B={yl y=-2x²+2 ,x∈R},求A∩B
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![设A={yl y=y²-1x∈R}.B={yl y=-2y²+2 ,x∈R},求A∩B设A={yl y=x²-1x∈R}.B={yl y=-2x²+2 ,x∈R},求A∩B](/uploads/image/z/12974173-61-3.jpg?t=%E8%AE%BEA%3D%EF%BD%9Byl+y%3Dy%26%23178%3B-1x%E2%88%88R%EF%BD%9D.B%3D%EF%BD%9Byl+y%3D-2y%26%23178%3B%2B2+%2Cx%E2%88%88R%7D%2C%E6%B1%82A%E2%88%A9B%E8%AE%BEA%3D%EF%BD%9Byl+y%3Dx%26%23178%3B-1x%E2%88%88R%EF%BD%9D.B%3D%EF%BD%9Byl+y%3D-2x%26%23178%3B%2B2+%2Cx%E2%88%88R%7D%2C%E6%B1%82A%E2%88%A9B)
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设A={yl y=y²-1x∈R}.B={yl y=-2y²+2 ,x∈R},求A∩B设A={yl y=x²-1x∈R}.B={yl y=-2x²+2 ,x∈R},求A∩B
设A={yl y=y²-1x∈R}.B={yl y=-2y²+2 ,x∈R},求A∩B
设A={yl y=x²-1x∈R}.B={yl y=-2x²+2 ,x∈R},求A∩B
设A={yl y=y²-1x∈R}.B={yl y=-2y²+2 ,x∈R},求A∩B设A={yl y=x²-1x∈R}.B={yl y=-2x²+2 ,x∈R},求A∩B
1.A、B:x没有关系,所以只要算出y 就行
2.y的取值与x有关,带进去就行
都无解。1.y²-1=2y²+2 ----------y²=-3-----------无解
2.x²-1=2x²+2 ---------x²=-3------------------无解
第一题,A、B就是分别解两个方程式,结果是空集
第二题,就是把两个式子连等,求得x=1,-1,在代入,求y,那么结果是{0}
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|说得对.都是空集