f[i-1]*2-(i>m)*f[i-m-1];其中(i>m)是什么用法啊,
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f[i-1]*2-(i>m)*f[i-m-1];其中(i>m)是什么用法啊,
f[i-1]*2-(i>m)*f[i-m-1];其中(i>m)是什么用法啊,
f[i-1]*2-(i>m)*f[i-m-1];其中(i>m)是什么用法啊,
(i>m) true 为1 false 为0
f[i-1]*2 + 0或1 * f[i-m-1]
f[i-1]*2-(i>m)*f[i-m-1];其中(i>m)是什么用法啊,
(1) B E H E I M I N ( )(2) C F I F K P K R ( ) (3)K F P ( ) (4)E I M ( )D M I ( ) A D G ( )
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sets:shiduan/1..5/:h,t; xinghao/1..3/:NN,m,MM,G,F,Q; link(xinghao,shiduan):n,w; endsets min=@sum(xinghao(i):(G(i)*t(1)+Q(i))*n(i,1)+(w(i,1)-m(i))*n(i,1)*F(i)*t(1))+ @sum(shiduan(j)|j #ge# 2:G(i)*n(i,j)*t(j)+(w(i,j)-m(i))*n(i,j)*F(j)*t(i)+@if(n(i,j)#g
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