解线性方程组 X1-X2+2X4+X5=0 3X1-3X2+7X4=0 X1-X2+2X3+3X4+2X5=0 2X1-2X2+2X3+7X4-3X5=0
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解线性方程组 X1-X2+2X4+X5=0 3X1-3X2+7X4=0 X1-X2+2X3+3X4+2X5=0 2X1-2X2+2X3+7X4-3X5=0
解线性方程组 X1-X2+2X4+X5=0 3X1-3X2+7X4=0 X1-X2+2X3+3X4+2X5=0 2X1-2X2+2X3+7X4-3X5=0
解线性方程组 X1-X2+2X4+X5=0 3X1-3X2+7X4=0 X1-X2+2X3+3X4+2X5=0 2X1-2X2+2X3+7X4-3X5=0
系数矩阵 A=
1 -1 0 2 1
3 -3 0 7 0
1 -1 2 3 2
2 -2 2 7 -3
r2-3r1,r3-r1,r4-2r1
1 -1 0 2 1
0 0 0 1 -3
0 0 2 1 1
0 0 2 3 -5
r1-2r2,r3-r2,r4-3r2
1 -1 0 0 7
0 0 0 1 -3
0 0 2 0 4
0 0 2 0 4
-->
1 -1 0 0 7
0 0 1 0 2
0 0 0 1 -3
0 0 0 0 0
方程组的通解为:c1(1,1,0,0,0)' + c2(-7,0,-2,3,1)'.
解线性方程组 X1-X2+2X4+X5=0 3X1-3X2+7X4=0 X1-X2+2X3+3X4+2X5=0 2X1-2X2+2X3+7X4-3X5=0
解线性方程组 X1-X2+2X4+X5=0 3X1-3X2+7X4=0 X1-X2+2X3+3X4+2X5=0 2X1-2X2+2X3+7X4-3X5=0
线性方程组 x1+x3+x4-x5=1,x2-x3-x4=-1,2x2-x5=0,x1-x3+x4=0帮我解出来
求齐次线性方程组的基础解系和通解 X1+X2-X3+2X4+X5=0 X3+3X4-X5=0 2X3+X4-2X5=0求齐次线性方程组的基础解系和通解 X1+X2-X3+2X4+X5=0 X3+3X4-X5=0 2X3+X4-2X5=0
求解线性方程组 x1-2x2+3x3-x4-x5=2 x1+x2-x3+x4-2x5=1 2x1-求解线性方程组x1-2x2+3x3-x4-x5=2x1+x2-x3+x4-2x5=12x1-x2+x3-2x5=22x1+2x2-5x3+2x4-x5=5
求线性方程组的全部解,并用对应导出组的基础解系表示X1+3X2+5X3-4X4=1 X1+3X2+2X3-2X4+X5=-1 X1-2X2+X3-X4-X5=3 X1-4X2+X3+X4-X5=3 X1+2X2+X3-X4+X5=-1
求非其次线性方程组 {x1+2x2+x3+x4+x5=1x1+2x2+x3+x4+x5=12x1+4x2+3x3+x4+x5=2-x1-2x2+x3+3x4-x5=5 2x3+4x4-2x5=6 的一般解
求非齐次线性方程组的通解x1+3x2+5x3-4x4=1x1+3x2+2x3-2x4+x5=-1x1-2x2+x3-x4-x5=3x1+2x2+x3-x4-x5=3
求下列齐次线性方程组的基础解系与通解.详见问题补充x1-2x2-x3-x4+x5=02x1+x2-x3+2x4-3x5=03x1-2x2-x3+x4-2x5=02x1-5x2+x3-2x4+2x5
判断下列奇次线性方程组是否有非零解?如果有,求其解.X1+X2+X3+4X4-3X5=0,X1-X2+3X3-2X4-X5=0,2X1+X2+3X3+5X4-5X5=0,3X1+X2+5X3+6X4-7X5=0
求下列非齐性线性方程组的解X1+ X2+ X3+ X4+ X5=32X1+ X2+3X3+3X4+4X5=143X1+4X2+ X3- 3X4+2X5=-11X1- X2+4X3+8X4+4X5=31
求下列其次线性方程组的基础解系,x1+ x2+2x3+2x4+7x5=02x1+3x2+4x3+5x4 =0 3x1+5x2+6x3+8x4 =0
解一道方程组x1+x2+x3=5,x2+x3+x4=1,x3+x4+x5=-5,x4+x5+x1=-3,x5+x1+x2=2
求解奇次线性方程组{上面2x1+x2+3x3+5x4-5x5 =0 中x1+x2+x3+4x4-3x5=0 下面3x1+x2+5x3+6x4-7x5=0
求线性方程组的全部解x1+x2-3x4-x5=2x1-x2+2x3-x4=14x1-2x2+6x3+3x4-4x5=82x1+4x2-2x3+4x4-7x5=9
感激不尽求线性方程组基础解系x1+x2+3x4-x5=0x1-x2+2x3-x4=04x1-2x2+6x3+3x4-4x5=02x1+4x2-2x3+4x4-7x5=0
问λ为何值时线性方程组有解,并求出解x1+x2+x3+x4+x5=λx1+2x3+3x4+2x5=34x1+5x2+3x3+2x4+3x5=2x1+x4+2x5=1
您好,判断a与b取什么值时,线性方程组有解?x1+x2+x3+x4+x5=13x1+2x2+x3+x4-3x5=ax2+2x3+2x4+6x5=35x1+4x2+3x3+3x4-x5=b