(1)如图,在凸五边形ABCDE中,AB⊥BC,AE⊥ED,∠BAC=∠EAD,P是CD的中点,求证:PB=PE.(提示:分别取AC、AD中点G、H,联接BG、GP、PH、HE)(2),若五边形为凹五边形,结论还成立吗?
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![(1)如图,在凸五边形ABCDE中,AB⊥BC,AE⊥ED,∠BAC=∠EAD,P是CD的中点,求证:PB=PE.(提示:分别取AC、AD中点G、H,联接BG、GP、PH、HE)(2),若五边形为凹五边形,结论还成立吗?](/uploads/image/z/13327929-9-9.jpg?t=%281%29%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E5%87%B8%E4%BA%94%E8%BE%B9%E5%BD%A2ABCDE%E4%B8%AD%2CAB%E2%8A%A5BC%2CAE%E2%8A%A5ED%2C%E2%88%A0BAC%3D%E2%88%A0EAD%2CP%E6%98%AFCD%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E6%B1%82%E8%AF%81%3APB%3DPE.%EF%BC%88%E6%8F%90%E7%A4%BA%EF%BC%9A%E5%88%86%E5%88%AB%E5%8F%96AC%E3%80%81AD%E4%B8%AD%E7%82%B9G%E3%80%81H%2C%E8%81%94%E6%8E%A5BG%E3%80%81GP%E3%80%81PH%E3%80%81HE%EF%BC%89%282%29%2C%E8%8B%A5%E4%BA%94%E8%BE%B9%E5%BD%A2%E4%B8%BA%E5%87%B9%E4%BA%94%E8%BE%B9%E5%BD%A2%2C%E7%BB%93%E8%AE%BA%E8%BF%98%E6%88%90%E7%AB%8B%E5%90%97%3F)
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