已知f(x)=(x-a)/ax(a>0) (1)判断并证明y=f(x)在x∈(0,+∞)上的单调性;(2)若存在X0,使f(x)=X0,则称X0为函数f(x)的不动点,现已知该函数有且仅有一个不动点,求a的值,并求不动点X0复制搜索
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![已知f(x)=(x-a)/ax(a>0) (1)判断并证明y=f(x)在x∈(0,+∞)上的单调性;(2)若存在X0,使f(x)=X0,则称X0为函数f(x)的不动点,现已知该函数有且仅有一个不动点,求a的值,并求不动点X0复制搜索](/uploads/image/z/13330744-16-4.jpg?t=%E5%B7%B2%E7%9F%A5f%28x%29%3D%28x-a%29%2Fax%28a%3E0%29+%281%29%E5%88%A4%E6%96%AD%E5%B9%B6%E8%AF%81%E6%98%8Ey%3Df%28x%29%E5%9C%A8x%E2%88%88%EF%BC%880%2C%2B%E2%88%9E%EF%BC%89%E4%B8%8A%E7%9A%84%E5%8D%95%E8%B0%83%E6%80%A7%EF%BC%9B%EF%BC%882%EF%BC%89%E8%8B%A5%E5%AD%98%E5%9C%A8X0%2C%E4%BD%BFf%28x%29%3DX0%2C%E5%88%99%E7%A7%B0X0%E4%B8%BA%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E4%B8%8D%E5%8A%A8%E7%82%B9%2C%E7%8E%B0%E5%B7%B2%E7%9F%A5%E8%AF%A5%E5%87%BD%E6%95%B0%E6%9C%89%E4%B8%94%E4%BB%85%E6%9C%89%E4%B8%80%E4%B8%AA%E4%B8%8D%E5%8A%A8%E7%82%B9%2C%E6%B1%82a%E7%9A%84%E5%80%BC%2C%E5%B9%B6%E6%B1%82%E4%B8%8D%E5%8A%A8%E7%82%B9X0%E5%A4%8D%E5%88%B6%E6%90%9C%E7%B4%A2)
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