作业帮(2x-3/5y-1/3z)(3/5y-1/3y+2x)帮忙哈!
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(2x-3/5y-1/3z)(3/5y-1/3y+2x)帮忙哈!
(2x-3/5y-1/3z)(3/5y-1/3y+2x)帮忙哈!
(2x-3/5y-1/3z)(3/5y-1/3y+2x)帮忙哈!
[2x-(3/5)y-(1/3)z][(3/5)y-(1/3)z+2x]={[2x-(1/3)z]-(3/5)y}{[2x-(1/3)z]+(3/5)y}
=[2x-(1/3)z]²-(9/25)y²=4x²-(4/3)xz+(1/9)z²-(9/25)y²
=4x²-(9/25)y²+(1/9)z²-(4/3)xz.
[原题有错,已改正]
(2x-3/5y-1/3z)(3/5y-1/3y+2x)
~~~~这里应该是1/3z 吧？！
(2x-3/5y-1/3z)(3/5y-1/3z+2x)
=[(2x- 1/3z)- 3/5y]*[(2x- 1/3z)+ 3/5y]
=(2x- 1/3z)²- (3/5y)²
=4x²- 4/3*xz+ 1/9*z²- 9/25*y²
(2x-3/5y-1/3z)(3/5y-1/3y+2x)
=[(2x-1/3z)-3/5y][(2x-1/3z)+3/5y]
=(2x-1/3z)²-(3/5y)²
=4x²-4/3xz+1/9z²-9/25y²
1.（x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2)
2(x+y-z)-3(x-y+z)-5(x+y-z)+6(x-y+z) 计算
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
x/2=y/3=z/5 x+3y-z/x-3y+z
方程组 (1) x+2y-3z=12 x-3y+2z= - 13 x-y-z=0 (2) x+ y=z 5x-y+z=18 2x+5y+3z= -1
x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2
因式分解：25x y^2 z^2 (x+y-z)-30xyz(z-x-y)^2+5x y z^3 (z-x-y)
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
{x+y+z=1 x-2y+3z=5 2x-3y-3z=-8
2x-y+3z=3 {3X+Y-2Z=-1 X+Y+Z=5
x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快
已知x:y:z=1:3:5,求（2x+3y-z)/(x+y-2z)的值
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5
x+y+z=2 x-3y+2z=1 2x+2y+z+5 要具体步骤..
3x-y+2z=-1 4x+y+z=5 x-2y-z=-2
{x+y+z=1 {x+3y+7z=-1 {x+5y+8z=2
x+y+z=-1 4x-2y+3z=5 y-z=8-2x