若f(x),g(x)在[a,b]上连续,(a,b)内可导,且g(x)≠0,试证明(a,b)内存在§ 使[f(a)-f(ξ)]/[g(ξ)-g(b)]=f'(ξ)/g'x)
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![若f(x),g(x)在[a,b]上连续,(a,b)内可导,且g(x)≠0,试证明(a,b)内存在§ 使[f(a)-f(ξ)]/[g(ξ)-g(b)]=f'(ξ)/g'x)](/uploads/image/z/13342722-42-2.jpg?t=%E8%8B%A5f%28x%29%2Cg%28x%29%E5%9C%A8%5Ba%2Cb%5D%E4%B8%8A%E8%BF%9E%E7%BB%AD%2C%28a%2Cb%29%E5%86%85%E5%8F%AF%E5%AF%BC%2C%E4%B8%94g%28x%29%E2%89%A00%2C%E8%AF%95%E8%AF%81%E6%98%8E%28a%2Cb%29%E5%86%85%E5%AD%98%E5%9C%A8%C2%A7+%E4%BD%BF%5Bf%28a%29-f%28%CE%BE%29%5D%2F%5Bg%28%CE%BE%29-g%28b%29%5D%3Df%27%28%CE%BE%29%2Fg%27x%29)
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