向量a=(cosx,sinx) b=(cosy,siny) 为什么它们的夹角是y-x a=(cosx,sinx)b=(cosy,siny)θ=y-xa+b=(cosx+cosy,sinx+siny)|a+b|=√(2+2cos(x-y))|a-b|=√(2-2cos(x-y))
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![向量a=(cosx,sinx) b=(cosy,siny) 为什么它们的夹角是y-x a=(cosx,sinx)b=(cosy,siny)θ=y-xa+b=(cosx+cosy,sinx+siny)|a+b|=√(2+2cos(x-y))|a-b|=√(2-2cos(x-y))](/uploads/image/z/13355994-66-4.jpg?t=%E5%90%91%E9%87%8Fa%3D%28cosx%2Csinx%29+b%3D%28cosy%2Csiny%29+%E4%B8%BA%E4%BB%80%E4%B9%88%E5%AE%83%E4%BB%AC%E7%9A%84%E5%A4%B9%E8%A7%92%E6%98%AFy-x+a%3D%28cosx%2Csinx%29b%3D%28cosy%2Csiny%29%CE%B8%3Dy-xa%2Bb%3D%28cosx%2Bcosy%2Csinx%2Bsiny%29%7Ca%2Bb%7C%3D%E2%88%9A%282%2B2cos%28x-y%29%29%7Ca-b%7C%3D%E2%88%9A%282-2cos%28x-y%29%29)
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