如图正方形CDEF的边长为4,截去一个角ABF得五边形ABCDE,已知AF=2,BF=1在AB上取一点P,过点P作CD、DE的平行线得矩形PNDM,求此矩形面积的最大值.
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![如图正方形CDEF的边长为4,截去一个角ABF得五边形ABCDE,已知AF=2,BF=1在AB上取一点P,过点P作CD、DE的平行线得矩形PNDM,求此矩形面积的最大值.](/uploads/image/z/13404374-62-4.jpg?t=%E5%A6%82%E5%9B%BE%E6%AD%A3%E6%96%B9%E5%BD%A2CDEF%E7%9A%84%E8%BE%B9%E9%95%BF%E4%B8%BA4%2C%E6%88%AA%E5%8E%BB%E4%B8%80%E4%B8%AA%E8%A7%92ABF%E5%BE%97%E4%BA%94%E8%BE%B9%E5%BD%A2ABCDE%2C%E5%B7%B2%E7%9F%A5AF%3D2%2CBF%3D1%E5%9C%A8AB%E4%B8%8A%E5%8F%96%E4%B8%80%E7%82%B9P%2C%E8%BF%87%E7%82%B9P%E4%BD%9CCD%E3%80%81DE%E7%9A%84%E5%B9%B3%E8%A1%8C%E7%BA%BF%E5%BE%97%E7%9F%A9%E5%BD%A2PNDM%2C%E6%B1%82%E6%AD%A4%E7%9F%A9%E5%BD%A2%E9%9D%A2%E7%A7%AF%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC.)
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