作业帮解不等式：根号(4-x2)+[x]/x>=0 (注：[ ]是绝对值）
来源：学生作业帮助网 编辑：作业帮 时间：2024/12/01 10:39:59
![解不等式：根号(4-x2)+[x]/x>=0 (注：[ ]是绝对值）](/uploads/image/z/1344423-39-3.jpg?t=%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8F%EF%BC%9A%E6%A0%B9%E5%8F%B7%284-x2%29%2B%5Bx%5D%2Fx%3E%3D0+%28%E6%B3%A8%EF%BC%9A%5B+%5D%E6%98%AF%E7%BB%9D%E5%AF%B9%E5%80%BC%EF%BC%89)
解不等式：根号(4-x2)+[x]/x>=0 (注：[ ]是绝对值）
解不等式：根号(4-x2)+[x]/x>=0 (注：[ ]是绝对值）
解不等式：根号(4-x2)+[x]/x>=0 (注：[ ]是绝对值）
x2是指x^2么?我先当是这样做了.
本题的关键在于对绝对值内正负的讨论
由于分母不能为0,显然x不等于0
当x>0时.原不等式转化为：x^2
因为x作分母，所以x不等于0.当x>0,4-x^2+1>0,得x>根号5;当x<0,4-x^2-1>0,得x<根号3.综上所述，x>根号5或x<根号3.
解不等式：√(4-x2)+|x|/x>=0 (注：[ ]是绝对值）
：√(4-x^2)+|x|/x>=
Domain 4-x ^ 2> = 0 -2 <= x <= 2,
the denominator of x is not equal to 0 if -2 <= x <0,
| x | =- x
so √ (4-x ^ 2) -1 > = 0
全部展开
解不等式：√(4-x2)+|x|/x>=0 (注：[ ]是绝对值）
：√(4-x^2)+|x|/x>=
Domain 4-x ^ 2> = 0 -2 <= x <= 2,
the denominator of x is not equal to 0 if -2 <= x <0,
| x | =- x
so √ (4-x ^ 2) -1 > = 0
√ (4-x ^ 2)> = 1
4-x ^ 2> = 1
x ^ 2 <= 3
- √ 3 <= x <= √ 3
because -2 <= x <0
So - √ 3 <= x <0 if 0 = 0 √ (4-x ^ 2)> = 0 Therefore,
√ (4-x ^ 2) +1> = 0
set up so
收起