[(a-6)/(1+b)]=-1a和b分别怎么解?[(a-6)/(1+b)]=-1[(-2ab-12)/((1+b)平方)]=-(3/2)
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![[(a-6)/(1+b)]=-1a和b分别怎么解?[(a-6)/(1+b)]=-1[(-2ab-12)/((1+b)平方)]=-(3/2)](/uploads/image/z/13575118-22-8.jpg?t=%5B%28a-6%29%2F%281%2Bb%29%5D%3D-1a%E5%92%8Cb%E5%88%86%E5%88%AB%E6%80%8E%E4%B9%88%E8%A7%A3%3F%5B%28a-6%29%2F%281%2Bb%29%5D%3D-1%5B%28-2ab-12%29%2F%28%281%2Bb%29%E5%B9%B3%E6%96%B9%29%5D%3D-%283%2F2%29)
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来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 00:20:24