求一到不等式题,
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求一到不等式题,
求一到不等式题,
求一到不等式题,
x2+x-2=(x+2)(x-1)
(x+2)(x-1)>0 推出x<-2 或者x>1
x2+x-2-4<=0推出(x+3)(x-2)《=0推出-2=<x=<3
取交集得1<x<=3