如图,已知AB分之AE = BC分之ED = AC分之AD 证明∠BAD=∠CAE

如图,已知AB分之AE = BC分之ED = AC分之AD 证明∠BAD=∠CAE 已知：如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC.求证：ED⊥AC. 已知：如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC 求证：ED⊥AC 已知,如图,ae垂直ab,bc垂直ab,ae=ab,ed=ac 求证 ed垂直ac 已知,如图,AB⊥BC,AE⊥ED,AB=AE, 已知:如图,AB⊥BC,AE⊥ED,AB=AE, 已知:如图,AB⊥BC,AE⊥ED,AB=AE∠ACD=∠ADC.求证:BC=ED请写过程,谢谢! 已知如图,AB⊥BC,AE⊥ED,AB=AE,∠ACD=∠ADC.求证:BC=ED 蟹蟹!2.如图,已知AB⊥BC,AE⊥ED,AB=BC,∠DCE=135°,说明AE=ED 如图,已知AB垂直于BC,AE垂直于ED,AB=BC,角DCE=135度,说明：AE=ED 如图,已知AB垂直于BC,AE垂直于ED,AB=BC,角DCE=135度,说明AE=ED 如图,已知AB垂直于BC,AE垂直于ED,AB=BC,角DCE=135度,说明：AE=ED 如图,已知AB=AE,BC=ED,AC=AD,求证:BE平行CD 如图,已知AE=AD,AB=AC,求证ED⊥BC 如图,AB=AE.BC=ED. 如图,AB=AE.BC=ED. 如图,已知：AB=AE,AC=AD,AC⊥AD,AB⊥AE.求证：ED⊥BC. 如图,AE⊥AB,BC⊥AB,CD⊥ED,ED=DC.求证：AE+BC=AB.