6x^2-640x+634≥0

6x^2-640x+634≥0 3≤|8-x| |x+1|>2-x |x+3|7|x+1| x^2-6|x|+9>0 |x-1|+|x+2|≥5 （1）方法 f(x)分段函数-x^2+x(x≥0),x^2+x(x 设偶函数f(x)满足f(x)=2ˆx-4(x≥0),则{x|f(x-2)>0}=1.{x|x〈-2或x〉4}2.{x|x〈0或X＞4}3.{x|x＜0或x＞6}4.{x|x＜-2或x＞2} *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || x(x*x-6x-9)-x(x*x-8x-15)+2x(3-x) 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x x(x+2)(x+6)+20x+6=0 (x^-2x)^-5(x^-2x)-6=0 (x+2)(x-3)(x-6)(x-1)=0 6/(x-1)-(x+2)/x(x-1)=0 已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值 如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值, 1/(x*x-2x-3)+2/(x*-x-6)+3/(x*x+3x+2)=0 y=x^2-2x (x≥0) -x^2-2x(x 求y=(x^2)+2x(x≥0) y=-x+2x(x 已知函数f(x)=x²+x+1,x≥0；2x+1,x 已知f(x)={x²+x+1,x≥0 2x+1,x