等差数列{an}中,d=2,n=5,an=-10,求a1及Sn

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等差数列{an}中,d=2,n=5,an=-10,求a1及Sn
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等差数列{an}中,d=2,n=5,an=-10,求a1及Sn
等差数列{an}中,d=2,n=5,an=-10,求a1及Sn

等差数列{an}中,d=2,n=5,an=-10,求a1及Sn
a5=a1+4d
-10=a1+8
a1=-18
S(5)=(a1+a5)*5/2
=(-18-10)*5/2
=-70

an=a1+4d=-10,a1=-18,sn=5*(-18)+5*4*2/2=-70

[高二数学]等差数列 {an} 的各项均为正数, aSn , {bn} 为等比数列, b1 = 1 且 b2*s2(2)3/4-1/2n-1/2n-2 an=a1 (n-

an=a1+(n-1)d
a1=-18
sn=-70