求角BOC与角A的关系因为BO平分角ABC,CO平分角ACB所以角1=1/2角ABC,角2等于1/2角ACB所以角BOC=180度-(角1+角2)=180度-(____+____)=180度-1/2(角ABC+角ACB)=180度-1/2(180度-___)=180度-90度+1/2角A=______________所以结论:__
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![求角BOC与角A的关系因为BO平分角ABC,CO平分角ACB所以角1=1/2角ABC,角2等于1/2角ACB所以角BOC=180度-(角1+角2)=180度-(____+____)=180度-1/2(角ABC+角ACB)=180度-1/2(180度-___)=180度-90度+1/2角A=______________所以结论:__](/uploads/image/z/14105558-38-8.jpg?t=%E6%B1%82%E8%A7%92BOC%E4%B8%8E%E8%A7%92A%E7%9A%84%E5%85%B3%E7%B3%BB%E5%9B%A0%E4%B8%BABO%E5%B9%B3%E5%88%86%E8%A7%92ABC%2CCO%E5%B9%B3%E5%88%86%E8%A7%92ACB%E6%89%80%E4%BB%A5%E8%A7%921%3D1%2F2%E8%A7%92ABC%2C%E8%A7%922%E7%AD%89%E4%BA%8E1%2F2%E8%A7%92ACB%E6%89%80%E4%BB%A5%E8%A7%92BOC%3D180%E5%BA%A6-%28%E8%A7%921%2B%E8%A7%922%29%3D180%E5%BA%A6-%28____%2B____%29%3D180%E5%BA%A6-1%2F2%28%E8%A7%92ABC%2B%E8%A7%92ACB%29%3D180%E5%BA%A6-1%2F2%28180%E5%BA%A6-___%29%3D180%E5%BA%A6-90%E5%BA%A6%2B1%2F2%E8%A7%92A%3D______________%E6%89%80%E4%BB%A5%E7%BB%93%E8%AE%BA%3A__)
求角BOC与角A的关系因为BO平分角ABC,CO平分角ACB所以角1=1/2角ABC,角2等于1/2角ACB所以角BOC=180度-(角1+角2)=180度-(____+____)=180度-1/2(角ABC+角ACB)=180度-1/2(180度-___)=180度-90度+1/2角A=______________所以结论:__
求角BOC与角A的关系
因为BO平分角ABC,CO平分角ACB
所以角1=1/2角ABC,角2等于1/2角ACB
所以角BOC=180度-(角1+角2)
=180度-(____+____)
=180度-1/2(角ABC+角ACB)
=180度-1/2(180度-___)
=180度-90度+1/2角A
=______________
所以结论:_____________.
汗...就这个结果啊
求角BOC与角A的关系因为BO平分角ABC,CO平分角ACB所以角1=1/2角ABC,角2等于1/2角ACB所以角BOC=180度-(角1+角2)=180度-(____+____)=180度-1/2(角ABC+角ACB)=180度-1/2(180度-___)=180度-90度+1/2角A=______________所以结论:__
因为BO平分角ABC,CO平分角ACB
所以角1=1/2角ABC,角2等于1/2角ACB
所以角BOC=180度-(角1+角2)
=180度-(1/2角ABC+1/2角ACB )
=180度-1/2(角ABC+角ACB)
=180度-1/2(180度-1/2角A)
=180度-90度+1/2角A
=90度+1/2角A
所以结论:90度+1/2角A
.
180度-(1/2角ABC+1/2角ACB)
=……
=180度-1/2(180度-角A)
=……
=90度+1/2角A
所以结论角BOC=90度+1/2角A