作业帮x^2+2x+y^2-8y+17=0,求x^y
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x^2+2x+y^2-8y+17=0,求x^y
x^2+2x+y^2-8y+17=0,求x^y
x^2+2x+y^2-8y+17=0,求x^y
x^2+2x+y^2-8y+17=0
(x+1)^2+(y-4)^2=0
∴x=-1,y=4
x^y=（-1）^4=1
(x²+2x+1)+(y²-8y+16)=0
(x+1(²+(y-4)²=0
所以x+1=y-4=0
x=-1,y=4
所以x的y次方=1
x^2+2x+y^2-8y+17=0
(x^2+2x+1)+(y^2-8y+16)=0
(x+1)^2+(y-4)^2=0
x=-1, y=4
x^y=(-1)^4=1
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