sina(1+cos2a)=sin2acosa该如何求证
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sina(1+cos2a)=sin2acosa该如何求证
sina(1+cos2a)=sin2acosa该如何求证
sina(1+cos2a)=sin2acosa该如何求证
sina=sin2acosa+cos2asina
=sin(2a-a)
1-cos2a/sina=2sina【过程,】
求证 1-cos2a/sina=2sina
cos2a/sina+π/4=1/2求cos2a
sin2a+sina/cos2a+cosa+1=
求证:sina(1+cos2a)=sin2a*cosa.
sinA=1/3,求cos2A
1+2(sina^2)+cos2a=,急
sinA*(1+cos2A)化简,
若(1+cos2a)/sina=2,则cosa-sina=
(cosA-cos2A)/(sinA+sin2A)=?
sina=cos2a 求tana
证明(sin2a/1-cos2a)*(cosa/1-sina)=1+sina/sina
证明(sin2a/1-cos2a)*(cosa/1-sina)=1+sina/sina
若sina=-1/3,则1+cos2a=多少
sina-cosa=1/2.cos2a=?
sina=3cosa,则cos2a/1+sin2a=
已知sina+cosa=1/3,则cos2a=
已知sina= 1/5则cos2a等于