1^2+3^2+5^2+.+N^2=多少

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1^2+3^2+5^2+.+N^2=多少
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1^2+3^2+5^2+.+N^2=多少
1^2+3^2+5^2+.+N^2=多少

1^2+3^2+5^2+.+N^2=多少
找规律
1²=1²
1²+3²=2²
1²+3²+5²=3²
1²+3²+5²+7²=4²
.
连续奇数平方和等于奇数个数的平方.
1^2+3^2+5^2+.+(2N-1)^2=N²
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N*(N+1)*(2N+1)/6

设f(N)=1^2 + 3^2 + 5^2 + ... + N^2=A1 + A2 * N + A3 * N^2 + A4 * N^3
N^2 = f(N) - f(N-2) = 2 * A2 + A3 * (4N - 4) + A4 * (6N^2-12N+8)
=A4 * 6N^2 +(4*A3-12*A4)N+(2*A2-4*A3+8*A4)
A4 = 1/6

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设f(N)=1^2 + 3^2 + 5^2 + ... + N^2=A1 + A2 * N + A3 * N^2 + A4 * N^3
N^2 = f(N) - f(N-2) = 2 * A2 + A3 * (4N - 4) + A4 * (6N^2-12N+8)
=A4 * 6N^2 +(4*A3-12*A4)N+(2*A2-4*A3+8*A4)
A4 = 1/6
4*A3-12*A4=0 => A3 = 1/2
2*A2-4*A3+8*A4=0 => A2 = 1/3
f(N) = A1+(N^3+3N^2+2N)/6=A1+N*(N+1)*(N+2)/6
f(1)=1, 则A1=0
f(N) = N*(N+1)*(N+2)/6

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