已知三角形ABC是等边三角形,AB=1,BD=CD,角BDC=120度.以D为顶点,作60度角,交AB于M,交AC于N,求三角型AMN的周长.
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![已知三角形ABC是等边三角形,AB=1,BD=CD,角BDC=120度.以D为顶点,作60度角,交AB于M,交AC于N,求三角型AMN的周长.](/uploads/image/z/14335661-29-1.jpg?t=%E5%B7%B2%E7%9F%A5%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E6%98%AF%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2CAB%3D1%2CBD%3DCD%2C%E8%A7%92BDC%3D120%E5%BA%A6.%E4%BB%A5D%E4%B8%BA%E9%A1%B6%E7%82%B9%2C%E4%BD%9C60%E5%BA%A6%E8%A7%92%2C%E4%BA%A4AB%E4%BA%8EM%2C%E4%BA%A4AC%E4%BA%8EN%2C%E6%B1%82%E4%B8%89%E8%A7%92%E5%9E%8BAMN%E7%9A%84%E5%91%A8%E9%95%BF.)
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