将下列各式化简为Asin(a+β)A>0sina-根号3cosa

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/05 01:41:16
将下列各式化简为Asin(a+β)A>0sina-根号3cosa
x){ɎӟNhyiϴX}n=3u-qr~qMR>1/ `G"FFZp $4& o7 6H&Tl.HTF 1Rw?

将下列各式化简为Asin(a+β)A>0sina-根号3cosa
将下列各式化简为Asin(a+β)A>0
sina-根号3cosa

将下列各式化简为Asin(a+β)A>0sina-根号3cosa
sina-√3cosa
=2(1/2*sina-√3/2*cosa)
=2(cosπ/3sina-sinπ/3cosa)
=2sin(a-π/3)