在平面直角坐标系中,点A向西运动,B点在X轴上运动,某一时刻∠ABC=∠ABD,作∠CBO的平分线与AC的延长线交于点E,作CF⊥BE于F,求证∠ABD=∠ECF.
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/07 02:38:09
![在平面直角坐标系中,点A向西运动,B点在X轴上运动,某一时刻∠ABC=∠ABD,作∠CBO的平分线与AC的延长线交于点E,作CF⊥BE于F,求证∠ABD=∠ECF.](/uploads/image/z/14348552-32-2.jpg?t=%E5%9C%A8%E5%B9%B3%E9%9D%A2%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E7%B3%BB%E4%B8%AD%2C%E7%82%B9A%E5%90%91%E8%A5%BF%E8%BF%90%E5%8A%A8%2CB%E7%82%B9%E5%9C%A8X%E8%BD%B4%E4%B8%8A%E8%BF%90%E5%8A%A8%2C%E6%9F%90%E4%B8%80%E6%97%B6%E5%88%BB%E2%88%A0ABC%3D%E2%88%A0ABD%2C%E4%BD%9C%E2%88%A0CBO%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E4%B8%8EAC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%A4%E4%BA%8E%E7%82%B9E%2C%E4%BD%9CCF%E2%8A%A5BE%E4%BA%8EF%2C%E6%B1%82%E8%AF%81%E2%88%A0ABD%EF%BC%9D%E2%88%A0ECF.)
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