已知向量a=(cos2x/3,sin3x/2),b=(cosx/2,-sinx/2),且x∈[0,π/2],若f(x)=a·b-2λla+bl的最小值为-3/2,求实数λ的值 我数学不好,过程尽量具体些,
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![已知向量a=(cos2x/3,sin3x/2),b=(cosx/2,-sinx/2),且x∈[0,π/2],若f(x)=a·b-2λla+bl的最小值为-3/2,求实数λ的值 我数学不好,过程尽量具体些,](/uploads/image/z/14563692-36-2.jpg?t=%E5%B7%B2%E7%9F%A5%E5%90%91%E9%87%8Fa%3D%EF%BC%88cos2x%2F3%2Csin3x%2F2%EF%BC%89%2Cb%3D%28cosx%2F2%2C-sinx%2F2%29%2C%E4%B8%94x%E2%88%88%5B0%2C%CF%80%2F2%5D%2C%E8%8B%A5f%28x%29%3Da%C2%B7b-2%CE%BBla%2Bbl%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E4%B8%BA-3%2F2%2C%E6%B1%82%E5%AE%9E%E6%95%B0%CE%BB%E7%9A%84%E5%80%BC+%E6%88%91%E6%95%B0%E5%AD%A6%E4%B8%8D%E5%A5%BD%2C%E8%BF%87%E7%A8%8B%E5%B0%BD%E9%87%8F%E5%85%B7%E4%BD%93%E4%BA%9B%2C)
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