已知集合m={z|z=x+i/1-xi,x1.已知集合m={z|z=(x+i)/(1-xi),x属于R},则m元素是什么?2.在三角形abc中,角bac大于90度,复数z=(cosb-sinc)+i(sinb-cosc)对应点位于复平面的第几象限?!
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/29 09:20:48
![已知集合m={z|z=x+i/1-xi,x1.已知集合m={z|z=(x+i)/(1-xi),x属于R},则m元素是什么?2.在三角形abc中,角bac大于90度,复数z=(cosb-sinc)+i(sinb-cosc)对应点位于复平面的第几象限?!](/uploads/image/z/14785611-51-1.jpg?t=%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88m%3D%7Bz%7Cz%3Dx%2Bi%2F1-xi%2Cx1.%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88m%3D%7Bz%7Cz%3D%EF%BC%88x%2Bi%EF%BC%89%2F%EF%BC%881-xi%EF%BC%89%2Cx%E5%B1%9E%E4%BA%8ER%7D%2C%E5%88%99m%E5%85%83%E7%B4%A0%E6%98%AF%E4%BB%80%E4%B9%88%3F2.%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2abc%E4%B8%AD%2C%E8%A7%92bac%E5%A4%A7%E4%BA%8E90%E5%BA%A6%2C%E5%A4%8D%E6%95%B0z%3D%28cosb-sinc%29%2Bi%28sinb-cosc%29%E5%AF%B9%E5%BA%94%E7%82%B9%E4%BD%8D%E4%BA%8E%E5%A4%8D%E5%B9%B3%E9%9D%A2%E7%9A%84%E7%AC%AC%E5%87%A0%E8%B1%A1%E9%99%90%3F%21)
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