..complex number如果z=cis (Θ),证明z+1/z=2cos(Θ)注意下:条件是"cis"( cos(Θ)+i sin(Θ),不是"cos"
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..complex number如果z=cis (Θ),证明z+1/z=2cos(Θ)注意下:条件是"cis"( cos(Θ)+i sin(Θ),不是"cos"
..complex number
如果z=cis (Θ),证明z+1/z=2cos(Θ)
注意下:条件是"cis"( cos(Θ)+i sin(Θ),不是"cos"
..complex number如果z=cis (Θ),证明z+1/z=2cos(Θ)注意下:条件是"cis"( cos(Θ)+i sin(Θ),不是"cos"
1/(cosΘ+isinΘ) 上下同乘(cosΘ-isinΘ),1/(cosΘ+isinΘ) =cosΘ-isinΘ
z+1/z=cosΘ+isinΘ +1/(cosΘ+isinΘ)= cosΘ+isinΘ+cosΘ-isinΘ =2cos(Θ)
即证
cis是什么…
..complex number如果z=cis (Θ),证明z+1/z=2cos(Θ)注意下:条件是cis( cos(Θ)+i sin(Θ),不是cos
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