等比数列a(n)通项公式为a(n)=2ˇn,求算a(i)×a(j)的和T(n) (1≤ i≤ j≤ n) 即 i 和j 为1到n项内任意两项T(n)=a1×[a1+a2+a3+a4+a5.+a(n)]+a2×[a2+a3+a4+a5...+a(n)]+a3×[a3+a4+a5...+a(n)]+.a(n-1)×[a(n-1)+a(n)
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![等比数列a(n)通项公式为a(n)=2ˇn,求算a(i)×a(j)的和T(n) (1≤ i≤ j≤ n) 即 i 和j 为1到n项内任意两项T(n)=a1×[a1+a2+a3+a4+a5.+a(n)]+a2×[a2+a3+a4+a5...+a(n)]+a3×[a3+a4+a5...+a(n)]+.a(n-1)×[a(n-1)+a(n)](/uploads/image/z/15145674-42-4.jpg?t=%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97a%EF%BC%88n%29%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%E4%B8%BAa%28n%29%3D2%CB%87n%2C%E6%B1%82%E7%AE%97a%28i%29%C3%97a%28j%29%E7%9A%84%E5%92%8CT%28n%29+%281%E2%89%A4+i%E2%89%A4+j%E2%89%A4+n%29+%E5%8D%B3+i+%E5%92%8Cj+%E4%B8%BA1%E5%88%B0n%E9%A1%B9%E5%86%85%E4%BB%BB%E6%84%8F%E4%B8%A4%E9%A1%B9T%28n%29%3Da1%C3%97%5Ba1%EF%BC%8Ba2%EF%BC%8Ba3%EF%BC%8Ba4%EF%BC%8Ba5.%EF%BC%8Ba%28n%29%5D%2Ba2%C3%97%5Ba2%EF%BC%8Ba3%EF%BC%8Ba4%EF%BC%8Ba5...%EF%BC%8Ba%28n%29%5D%2Ba3%C3%97%5Ba3%2Ba4%2Ba5...%EF%BC%8Ba%28n%29%5D%EF%BC%8B.a%28n-1%29%C3%97%5Ba%28n-1%29%2Ba%28n%29)
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