在梯形ABCD中,AB//CD,两对角线交于M,若AD=BD,AC=AB,角ADB=90度已知在梯形ABCD中,AB//CD,对角线AC、BD相交于点E,对角线BD=AD,AC=AB,且角ADB=90度,求(1)角CAB=30度(2)BE=BC
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![在梯形ABCD中,AB//CD,两对角线交于M,若AD=BD,AC=AB,角ADB=90度已知在梯形ABCD中,AB//CD,对角线AC、BD相交于点E,对角线BD=AD,AC=AB,且角ADB=90度,求(1)角CAB=30度(2)BE=BC](/uploads/image/z/15190348-4-8.jpg?t=%E5%9C%A8%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAB%2F%2FCD%2C%E4%B8%A4%E5%AF%B9%E8%A7%92%E7%BA%BF%E4%BA%A4%E4%BA%8EM%2C%E8%8B%A5AD%3DBD%2CAC%3DAB%2C%E8%A7%92ADB%3D90%E5%BA%A6%E5%B7%B2%E7%9F%A5%E5%9C%A8%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAB%2F%2FCD%2C%E5%AF%B9%E8%A7%92%E7%BA%BFAC%E3%80%81BD%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9E%2C%E5%AF%B9%E8%A7%92%E7%BA%BFBD%3DAD%2CAC%3DAB%2C%E4%B8%94%E8%A7%92ADB%3D90%E5%BA%A6%2C%E6%B1%82%EF%BC%881%EF%BC%89%E8%A7%92CAB%3D30%E5%BA%A6%EF%BC%882%EF%BC%89BE%3DBC)
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