matlab 用ode45解决二元微分方程,有两个初始条件function D2y=fun(t,y)Dy=zeros(2,1);D2y(1)=-f*M*y(1)/(y(1)^2+y(2)^2)^1.5;D2y(2)=-f*M*y(2)/(y(1)^2+y(2)^2)^1.5;这是函数但是有两个初始条件,不但有初值,还有一阶导数的初
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![matlab 用ode45解决二元微分方程,有两个初始条件function D2y=fun(t,y)Dy=zeros(2,1);D2y(1)=-f*M*y(1)/(y(1)^2+y(2)^2)^1.5;D2y(2)=-f*M*y(2)/(y(1)^2+y(2)^2)^1.5;这是函数但是有两个初始条件,不但有初值,还有一阶导数的初](/uploads/image/z/15207635-11-5.jpg?t=matlab+%E7%94%A8ode45%E8%A7%A3%E5%86%B3%E4%BA%8C%E5%85%83%E5%BE%AE%E5%88%86%E6%96%B9%E7%A8%8B%2C%E6%9C%89%E4%B8%A4%E4%B8%AA%E5%88%9D%E5%A7%8B%E6%9D%A1%E4%BB%B6function+D2y%3Dfun%28t%2Cy%29Dy%3Dzeros%282%2C1%29%3BD2y%281%29%3D-f%2AM%2Ay%281%29%2F%28y%281%29%5E2%2By%282%29%5E2%29%5E1.5%3BD2y%282%29%3D-f%2AM%2Ay%282%29%2F%28y%281%29%5E2%2By%282%29%5E2%29%5E1.5%3B%E8%BF%99%E6%98%AF%E5%87%BD%E6%95%B0%E4%BD%86%E6%98%AF%E6%9C%89%E4%B8%A4%E4%B8%AA%E5%88%9D%E5%A7%8B%E6%9D%A1%E4%BB%B6%2C%E4%B8%8D%E4%BD%86%E6%9C%89%E5%88%9D%E5%80%BC%2C%E8%BF%98%E6%9C%89%E4%B8%80%E9%98%B6%E5%AF%BC%E6%95%B0%E7%9A%84%E5%88%9D)
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