三角函数题
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三角函数题
三角函数题
三角函数题
f(sinx)
=f[cos(π/2-x)]
=cos[17(π/2-x)]
=cos(17π/2-17x)
=cos(8π+π/2-17x)
=cos(π/2-17x)
=sin17x
命题得证
f(sinx) = f(cos(π/2-x))
= cos17(π/2-x)
= cos(17π/2 - 17x)
= cos(π/2 - 17x)
= sin17x
f[cos(派/2+X)=cos17(派/2+X)
f[sin(-X)]=-sin17X f(sinX)=sin17X