若log4底[log3底(log2底x)]=0,则x=?

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若log4底[log3底(log2底x)]=0,则x=?
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若log4底[log3底(log2底x)]=0,则x=?
若log4底[log3底(log2底x)]=0,则x=?

若log4底[log3底(log2底x)]=0,则x=?
从外到里计算 log4底[log3底(log2底x)]=0
log3底(log2底x)]=1 log2底x)]= 3 x=8

log4底[log3底(log2底x)]=0
log3底(log2底x)=1
log2底x=3
x=2^3