如图,角1=角2,AB*AD=AC*AE,求证;ABC∽△AED

如图,DE//BC,请问AD:AC=AE:AB?AD:AE=AB:AC? 已知:如图,角1=角2,角3=角4,AC=AB.求证AE=AD 已知：如图,AC=AB,角1=角2,角3=角4,求证：AE=AD 如图,角1=角2,角3=角4,AE=AD.求证AC=AB 已知,如图,角1=角2,角3＝角4,AC=AB,求证AE=AD 如图已知AB=AD,AC=AE,角1等于角2 证明角1等于角CDE 如图,已知AB=AC,AD=AE,BD=CE,求证,角3=角1+角2 如图已知AB=AE AC=AD 角1=角2求证BF=EG 如图,已知Ab =AD,AC=AE,角1=角2,求证：BC=DE 如图,已知,AB=AC,AD=AE,角1=角2,求证：BD=CE 如图,已知角1=角2,AB=AC,AE=AD.求证:BD=EC 如图,AD=AE,BE=CD,角1=角2,求证:AB=AC? 如图,三角形ABCX中,AC=AB,AD=AE,角1=角2,说明OB=OC 如图,在三角形ABC中,AB=AC,角1=角2,是说明AE=AD 如图,角1=角2,AB*AD=AC*AE,求证;ABC∽△AED 如图,AD是三角形ABC的中线,AE垂直AC,AF垂直AB,且AE=AC,AF=AB,求证：AD=1/2EF 已知,如图,AB⊥AC,AB=AC,AD⊥'AE,AD=AE,求证:(1)BE=CD;(2)BC⊥CD急!帮个忙呗! 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证:(1)△DAC≌△EAB;(2)BE⊥CD. ,の