已知x,y,z满足(1)已知|x-2|+(y+3)2=0(2)z是最大的负整数化简求值2(x2y+xyz)-3(x2y-xyz)-4x2y已知x,y,z满足:(1)已知|x-2|+(y+3)2=0,(2)z是最大的负整数,化简求值:2(x2y+xyz)-3(x2y-xyz)-
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![已知x,y,z满足(1)已知|x-2|+(y+3)2=0(2)z是最大的负整数化简求值2(x2y+xyz)-3(x2y-xyz)-4x2y已知x,y,z满足:(1)已知|x-2|+(y+3)2=0,(2)z是最大的负整数,化简求值:2(x2y+xyz)-3(x2y-xyz)-](/uploads/image/z/1612617-33-7.jpg?t=%E5%B7%B2%E7%9F%A5x%2Cy%2Cz%E6%BB%A1%E8%B6%B3%EF%BC%881%EF%BC%89%E5%B7%B2%E7%9F%A5%7Cx-2%7C%2B%EF%BC%88y%2B3%EF%BC%892%3D0%EF%BC%882%EF%BC%89z%E6%98%AF%E6%9C%80%E5%A4%A7%E7%9A%84%E8%B4%9F%E6%95%B4%E6%95%B0%E5%8C%96%E7%AE%80%E6%B1%82%E5%80%BC2%EF%BC%88x2y%2Bxyz%EF%BC%89-3%EF%BC%88x2y-xyz%EF%BC%89-4x2y%E5%B7%B2%E7%9F%A5x%2Cy%2Cz%E6%BB%A1%E8%B6%B3%EF%BC%9A%EF%BC%881%EF%BC%89%E5%B7%B2%E7%9F%A5%7Cx-2%7C%2B%EF%BC%88y%2B3%EF%BC%892%3D0%2C%EF%BC%882%EF%BC%89z%E6%98%AF%E6%9C%80%E5%A4%A7%E7%9A%84%E8%B4%9F%E6%95%B4%E6%95%B0%2C%E5%8C%96%E7%AE%80%E6%B1%82%E5%80%BC%EF%BC%9A2%EF%BC%88x2y%2Bxyz%EF%BC%89-3%EF%BC%88x2y-xyz%EF%BC%89-)
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已知x,y,z满足(1)已知|x-2|+(y+3)2=0(2)z是最大的负整数化简求值2(x2y+xyz)-3(x2y-xyz)-4x2y已知x,y,z满足:(1)已知|x-2|+(y+3)2=0,(2)z是最大的负整数,化简求值:2(x2y+xyz)-3(x2y-xyz)-
已知x,y,z满足(1)已知|x-2|+(y+3)2=0(2)z是最大的负整数化简求值2(x2y+xyz)-3(x2y-xyz)-4x2y
已知x,y,z满足:(1)已知|x-2|+(y+3)2=0,(2)z是最大的负整数,化简求值:2(x2y+xyz)-3(x2y-xyz)-4x2y.(老师怎么做?最好写清过程)
已知x,y,z满足(1)已知|x-2|+(y+3)2=0(2)z是最大的负整数化简求值2(x2y+xyz)-3(x2y-xyz)-4x2y已知x,y,z满足:(1)已知|x-2|+(y+3)2=0,(2)z是最大的负整数,化简求值:2(x2y+xyz)-3(x2y-xyz)-
|x-2|+(y+3)²=0
都是非负式
所以分别都=0
所以x-2=0
y+3=0
所以
x=2
y=-3
又因为z是最大的负整数
所以z=-1
原式=2(x²y+xyz)-3(x²y-xyz)-4x²y
=2x²y+2xyz-3x²y+3xyz-4x²y
=-5x²y+5xyz
=-5xy(x-z)
把x=2,y=-3,z=-1代入原式
得
=-5×2×(-3)×(2+1)
=-10×(-3)×3
=30×3
=90
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