a²(x²-x+1)-a(x²-1)一元二次方程a²(x²-x+1)-a(x²-1)=(a²-1)x (a≠0且a≠1)
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a²(x²-x+1)-a(x²-1)一元二次方程a²(x²-x+1)-a(x²-1)=(a²-1)x (a≠0且a≠1)
a²(x²-x+1)-a(x²-1)一元二次方程
a²(x²-x+1)-a(x²-1)=(a²-1)x (a≠0且a≠1)
a²(x²-x+1)-a(x²-1)一元二次方程a²(x²-x+1)-a(x²-1)=(a²-1)x (a≠0且a≠1)
a²(x²-x+1)-a(x²-1)=(a²-1)x (a≠0且a≠1)
a²(x²-x+1)-a(x²-1)-(a²-1)x = 0
a²x²-a²x+a²-ax²+a-a²x+x = 0
a(a-1)x² - (2a²-1)x + a(a+1) = 0
{ ax-(a+1) } { (a-1)x -a } = 0
x1 = (a+1)/a,x2 = a/(a-1)
整理得 (a²-a)x²-(1-2a²)x+a²+a=0
十字相乘得 (ax-a-1)[(a-1)x-a]=0
所以ax-a-1=0或(a-1)x-a=0
所以x=(a+1)/a 或 x=a/(a-1)
1. a²(x²-x+1)-a(x²-1)=(a²-1)x (a≠0且a≠1)
2. a²(x²-x+1)-a(x²-1)=(a²-1)x (a≠0且a≠1)
a²(x²-x+1)-a(x²-1)-(a&s...
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1. a²(x²-x+1)-a(x²-1)=(a²-1)x (a≠0且a≠1)
2. a²(x²-x+1)-a(x²-1)=(a²-1)x (a≠0且a≠1)
a²(x²-x+1)-a(x²-1)-(a²-1)x = 0
a²x²-a²x+a²-ax²+a-a²x+x = 0
a(a-1)x² - (2a²-1)x + a(a+1) = 0
{ ax-(a+1) } { (a-1)x -a } = 0
x1 = (a+1)/a,x2 = a/(a-1)
3. 整理得 (a²-a)x²-(1-2a²)x+a²+a=0
十字相乘得 (ax-a-1)[(a-1)x-a]=0
所以ax-a-1=0或(a-1)x-a=0
所以x=(a+1)/a 或 x=a/(a-1)
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