三角函数题~(选择)已知 (sinx-2cosx)(3+2sinx+2cosx)=0,则(sin2x+2cos^2x)/(1+tanx)的值为多少?A 8/5 B 5/8 C 2/5 D 5/2
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![三角函数题~(选择)已知 (sinx-2cosx)(3+2sinx+2cosx)=0,则(sin2x+2cos^2x)/(1+tanx)的值为多少?A 8/5 B 5/8 C 2/5 D 5/2](/uploads/image/z/1675157-5-7.jpg?t=%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0%E9%A2%98%7E%EF%BC%88%E9%80%89%E6%8B%A9%EF%BC%89%E5%B7%B2%E7%9F%A5+%28sinx-2cosx%29%283%2B2sinx%2B2cosx%29%3D0%2C%E5%88%99%28sin2x%2B2cos%5E2x%29%2F%281%2Btanx%29%E7%9A%84%E5%80%BC%E4%B8%BA%E5%A4%9A%E5%B0%91%3FA+8%2F5+B+5%2F8+C+2%2F5+D+5%2F2)
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