1.已知△ABC的两边AB、AC的长是关于x的方程x²-(2k+3)x+k²+3k+2=0的两个实数根,第三边BC的长为5,问:k取何值时,△ABC是以BC为斜边的直角三角形?2.已知a是实数,且方程x²+2ax+1=0有两个不相
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![1.已知△ABC的两边AB、AC的长是关于x的方程x²-(2k+3)x+k²+3k+2=0的两个实数根,第三边BC的长为5,问:k取何值时,△ABC是以BC为斜边的直角三角形?2.已知a是实数,且方程x²+2ax+1=0有两个不相](/uploads/image/z/1690184-56-4.jpg?t=1.%E5%B7%B2%E7%9F%A5%E2%96%B3ABC%E7%9A%84%E4%B8%A4%E8%BE%B9AB%E3%80%81AC%E7%9A%84%E9%95%BF%E6%98%AF%E5%85%B3%E4%BA%8Ex%E7%9A%84%E6%96%B9%E7%A8%8Bx%26%23178%3B-%EF%BC%882k%2B3%EF%BC%89x%2Bk%26%23178%3B%2B3k%2B2%3D0%E7%9A%84%E4%B8%A4%E4%B8%AA%E5%AE%9E%E6%95%B0%E6%A0%B9%2C%E7%AC%AC%E4%B8%89%E8%BE%B9BC%E7%9A%84%E9%95%BF%E4%B8%BA5%2C%E9%97%AE%EF%BC%9Ak%E5%8F%96%E4%BD%95%E5%80%BC%E6%97%B6%2C%E2%96%B3ABC%E6%98%AF%E4%BB%A5BC%E4%B8%BA%E6%96%9C%E8%BE%B9%E7%9A%84%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2%3F2.%E5%B7%B2%E7%9F%A5a%E6%98%AF%E5%AE%9E%E6%95%B0%2C%E4%B8%94%E6%96%B9%E7%A8%8Bx%26%23178%3B%2B2ax%2B1%3D0%E6%9C%89%E4%B8%A4%E4%B8%AA%E4%B8%8D%E7%9B%B8)
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