4道数学题,二次函数的解析式1:y=ax²+bx经过点(2,2)和点(-1,5)求二次函数解析式2:已知抛物线y=x²-kx+2的顶点在坐标轴上,求K的值.3:二次函数经过点(-1,6)(2,9)(0,3)求二次函数
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![4道数学题,二次函数的解析式1:y=ax²+bx经过点(2,2)和点(-1,5)求二次函数解析式2:已知抛物线y=x²-kx+2的顶点在坐标轴上,求K的值.3:二次函数经过点(-1,6)(2,9)(0,3)求二次函数](/uploads/image/z/1690812-36-2.jpg?t=4%E9%81%93%E6%95%B0%E5%AD%A6%E9%A2%98%2C%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F1%EF%BC%9Ay%3Dax%26sup2%3B%2Bbx%E7%BB%8F%E8%BF%87%E7%82%B9%EF%BC%882%2C2%EF%BC%89%E5%92%8C%E7%82%B9%EF%BC%88-1%2C5%EF%BC%89%E6%B1%82%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%E8%A7%A3%E6%9E%90%E5%BC%8F2%EF%BC%9A%E5%B7%B2%E7%9F%A5%E6%8A%9B%E7%89%A9%E7%BA%BFy%3Dx%26sup2%3B-kx%2B2%E7%9A%84%E9%A1%B6%E7%82%B9%E5%9C%A8%E5%9D%90%E6%A0%87%E8%BD%B4%E4%B8%8A%2C%E6%B1%82K%E7%9A%84%E5%80%BC.3%EF%BC%9A%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%E7%BB%8F%E8%BF%87%E7%82%B9%EF%BC%88-1%2C6%EF%BC%89%EF%BC%882%2C9%EF%BC%89%EF%BC%880%2C3%EF%BC%89%E6%B1%82%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0)
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