设{an}是等差数列,bn=(1/2)^an,已知b1+b2+b3=21/8,b1b2b3=1/8,求an过cheng
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![设{an}是等差数列,bn=(1/2)^an,已知b1+b2+b3=21/8,b1b2b3=1/8,求an过cheng](/uploads/image/z/1747386-18-6.jpg?t=%E8%AE%BE%7Ban%7D%E6%98%AF%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%2Cbn%3D%281%2F2%29%5Ean%2C%E5%B7%B2%E7%9F%A5b1%2Bb2%2Bb3%3D21%2F8%2Cb1b2b3%3D1%2F8%2C%E6%B1%82an%E8%BF%87cheng)
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