(1+1/11+1/13+1/17)×(1/11+1/13+1/17+1/19)-(1+1/11+1/131/17+1/19)×(1/11+1/13+1/17)递等式运算
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![(1+1/11+1/13+1/17)×(1/11+1/13+1/17+1/19)-(1+1/11+1/131/17+1/19)×(1/11+1/13+1/17)递等式运算](/uploads/image/z/1748330-26-0.jpg?t=%EF%BC%881%2B1%2F11%2B1%2F13%2B1%2F17%EF%BC%89%C3%97%EF%BC%881%2F11%2B1%2F13%2B1%2F17%2B1%2F19%EF%BC%89%EF%BC%8D%EF%BC%881%2B1%2F11%2B1%2F131%2F17%2B1%2F19%EF%BC%89%C3%97%EF%BC%881%2F11%2B1%2F13%2B1%2F17%EF%BC%89%E9%80%92%E7%AD%89%E5%BC%8F%E8%BF%90%E7%AE%97)
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(1+1/11+1/13+1/17)×(1/11+1/13+1/17+1/19)-(1+1/11+1/131/17+1/19)×(1/11+1/13+1/17)递等式运算
(1+1/11+1/13+1/17)×(1/11+1/13+1/17+1/19)-(1+1/11+1/131/17+1/19)×(1/11+1/13+1/17)
递等式运算
(1+1/11+1/13+1/17)×(1/11+1/13+1/17+1/19)-(1+1/11+1/131/17+1/19)×(1/11+1/13+1/17)递等式运算
令1+1/11+1/13+1/17+1/19=a;1+1/11+1/13+1/17=b;
则有:
b×(a-1)-a×(b-1)
=ab-b-ab+a
=a-b;
=1/19;
这也是递等式运算,只不过用a,b代替复杂的算式而已,你不信明天等着老师讲,你们老师肯定也是这样写的
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,
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