作业帮等差数列{an}与{bn},它们的前n项之和分别为Sn,S'n,如果Sn/S'n=(7n+1)/(4n+27)(n∈N*),则a11/b11的值是
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等差数列{an}与{bn},它们的前n项之和分别为Sn,S'n,如果Sn/S'n=(7n+1)/(4n+27)(n∈N*),则a11/b11的值是
等差数列{an}与{bn},它们的前n项之和分别为Sn,S'n,如果Sn/S'n=(7n+1)/(4n+27)(n∈N*),则a11/b11的值是
等差数列{an}与{bn},它们的前n项之和分别为Sn,S'n,如果Sn/S'n=(7n+1)/(4n+27)(n∈N*),则a11/b11的值是
S(2n-1)=(a1+a2n-1)(2n-1)/2=an(2n-1)
S'(2n-1)=(b1+b2n-1)(2n-1)/2=bn(2n-1)
两式相除：S(2n-1)/S'(2n-1)=an/bn
a11/b11的值=S21/S'21=(7*21+1)/(4*21+27)=4/3
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