已知函数f(x)=2√3sin(x/2)cos(x/2)-(cos²x/2-sin²x/2)⑴求函数f(x)的单调递增区间;⑵若f(x)=0,求(sinx+cos(π+x)/(sinx+sin(π/2-x)的值
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![已知函数f(x)=2√3sin(x/2)cos(x/2)-(cos²x/2-sin²x/2)⑴求函数f(x)的单调递增区间;⑵若f(x)=0,求(sinx+cos(π+x)/(sinx+sin(π/2-x)的值](/uploads/image/z/1786390-70-0.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D2%E2%88%9A3sin%28x%2F2%29cos%28x%2F2%29-%28cos%26%23178%3Bx%2F2-sin%26%23178%3Bx%2F2%29%E2%91%B4%E6%B1%82%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%E5%8C%BA%E9%97%B4%EF%BC%9B%E2%91%B5%E8%8B%A5f%28x%29%3D0%2C%E6%B1%82%EF%BC%88sinx%2Bcos%28%CF%80%2Bx%EF%BC%89%2F%EF%BC%88sinx%2Bsin%28%CF%80%2F2-x%EF%BC%89%E7%9A%84%E5%80%BC)
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